![]() Hence the correct option here is C) 48 km/hr. The product of s1 ×t1 s 1 × t 1, and s2 ×t2 s 2 × t 2 gives the distances covered in time intervals t1 t 1, and t2 t 2 respectively. We found that the stone's velocity is 0 m/s after three seconds, when it is at a height of 45 metres. Average Speed (Total distance)/(Total Time) (1800 + 1800)/(30 + 45) 3600/75 48 km/hr. Case 1: For a body or object traveling with a speed of s1 s 1 for time t1 t 1, and the speed of s2 s 2 for time t2 t 2, the formula for average speed is given in the below expression. The acceleration is taken as \(-10\) m/s\(^2\). We return to the example of the stone being launched vertically upwards from ground level with an initial velocity of 30 m/s. ![]() ![]() We will look at examples involving motion with constant acceleration. Content Average velocity and average speedīefore turning our attention to problems involving non-constant acceleration and using calculus, we consider the concept of average velocity.
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